0=-28+16t-16t^2

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Solution for 0=-28+16t-16t^2 equation: 



0=-28+16t-16t^2

We move all terms to the left:

0-(-28+16t-16t^2)=0

We add all the numbers together, and all the variables

-(-28+16t-16t^2)=0

We get rid of parentheses

16t^2-16t+28=0

a = 16; b = -16; c = +28;
Δ = b2-4ac
Δ = -162-4·16·28
Δ = -1536
Delta is less than zero, so there is no solution for the equation

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